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Retko Kolo

Found in balk2.abc from the John Chambers abc collection
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Retko Kolo - staff notation
X: 420
T:Retko Kolo
O:Serbia
S:Ciga and Ivon Despotovic vol 1.
M: 4/4
L: 1/8
Q: 1/4=320
K:G 
P:A
%%MIDI program 42
%%MIDI gchord fzfz
%0
"d"(3cBc BA "f#" ^GA Bc|\
"d" zA2 "f#" c<c c B<A|\
"g" ^G/A/ z3 cccB|\
B2 D2 =FG ^G2|
"d" zA2z "f#" Bz =Gz|\
"e" E2 Az "g#" Gz D2|\
"a"^A/G/^F/E/ FE Ez Dz|\
"e"^Fz GA "a" z2 B2|
"d" cc BA "f#" ^GA cz|\
"d" .B2 .G2 "f#".F2 .A2|\
%10
"g" F2 ez dz cz|\
"e" Bz Dz "g" FG ^GA|
"g" Az ^cz Bz F2|\
"a" Az G2 Fz G2|\
"a" F/=F/2 Ee ^cAz3|
%0
"d"(3CB,C B,A, "F#" ^G,A, B,C|\
"d" zA,2 "F#" C<C C B,<A,|\
"g" ^G,/A,/ z3 CCCB,|\
B,2 D,2 =F,G, ^G,2|
"d" zA,2z "F#" B,z =G,z|\
"e" E,2 A,z "G#" G,z D,2|\
"a"^A,/G,/^F,/E,/ F,E, E,z D,z|\
"e"^F,z G,A, "A" z2 B,2|
"d" CC B,A, "F#" ^G,A, Cz|\
"d" .B,2 .G,2 "F#".F,2 .A,2|\
%10
"g" F,2 Ez Dz Cz|\
"e" B,z D,z "G" F,G, ^G,A,|
"g" A,z ^Cz B,z F,2|\
"a" A,z G,2 F,z G,2|\
"a" F,/=F,/2 E,E ^CA,z3|
P:B
M: 2/4
L: 1/16
K:D 
|:
"a" z2ED ^D2=D2| \
    (3.C4.C4.C4| \
   C2z2   C4   | \
  .C4     .A4  |
  .C4      D2F2| \
  F2E2     z4  | \
  FEF2    z4   | \
  (3.G4 .G4 .F4|
  E2E2    D4   | \
  c2 ^A2 =A2 A2| \
(3G2F2G2  z2^A2| \
   A4        G4|
z2 F2        A4| \
G2 z2      D4  | \
^G2 =G2 F2 E2  | \
=F2 E2  ^F2 z2 |
G2 z2     A2 z2| \
"g" (3B2A2B2 z2 B2| \
.B4     .B4    | \
.B4     .B4    |
.B4     .B4    | \
 B2 ^d2  c2 z2 | \
 A2 z2   B4    | \
"d" G4      A4 |
"g" F2 G2 z2 G2| \
"e" E2 E2   F2 z2  | \
"g".D4      .D4   | \
"g" F2 z2   A2 G2  |
"g" F2 z2   G2G2   | \
"a" F2 E2  E2 z2   :|
P:C
M: 4/4
L: 1/4
K:G 
"a"^c=c "g"  BB|  \
"g" BB "d"   BB| \
"g" BB  (3Bcc|  \
"g" AB "d"    GA| 
"g" (3FGF "e" E<E|  \
"g#" F>D  "f#"FA/2G/2| \
"g#"  FE "a"  E2  |  \
"a"z3/2^C/2 "d" AB|
"a" c^c    dB   |
"g" BB    BB| \
"a" BB "g" B=c/2c/2 | \
"g" AB "d"    GA| \
"g" (3FAG "e" (3EFF| 
"g#" Ad "g" F/2zG/2| \
"g" FG  "a" F/2<E/2E |
P:D
M: 4/4
L: 1/8
K:A 
|:z4      zz/2 F/2 =FF|\
"a" EzE3/2d/2  dcd/2c3/2|\
"a" cz  c2     dc    =cB|\
"e" Bz  B2   "g#" ^cB   ^A=A|
"a" Az  E2     AB  AB   |\
 (3 =fdc  dc  zc  z/2A3/2|\
"e" B/2z3/2 B2   "g#"    BG2d|\
"a" cB ^A=A       AE3    |
"e" Az  G2  "g#" FD/2 =F2 E/2 |\
"a" z4      (3=ded (3dBB|\
"e"    z4 "g#"  =c/2d/2^c (3B=cB|\
"a" z4         (3=c^cB ^A=A |\
"a" z4             AB    AB     |\
"a" ddcc    z2    A2     |
"e" BAB2    "g#" Bz    G2     |\
 cBAA             zz/2 F/2 =FF:|\

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